(7x+1)(x-4)=7x^2-27x-4

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Solution for (7x+1)(x-4)=7x^2-27x-4 equation: 



(7x+1)(x-4)=7x^2-27x-4

We move all terms to the left:

(7x+1)(x-4)-(7x^2-27x-4)=0

We get rid of parentheses

-7x^2+(7x+1)(x-4)+27x+4=0

We multiply parentheses ..

-7x^2+(+7x^2-28x+x-4)+27x+4=0

We get rid of parentheses

-7x^2+7x^2-28x+x+27x-4+4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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